===== Convert string to date ===== ==== single date string; without pandas; to datetime.date ==== Use from datetime import datetime datetime.strptime(date_str, date_fmt).date() Example: $ ipython Python 3.10.6 | packaged by conda-forge | (main, Oct 24 2022, 16:02:16) [MSC v.1916 64 bit (AMD64)] Type 'copyright', 'credits' or 'license' for more information IPython 8.4.0 -- An enhanced Interactive Python. Type '?' for help. In [1]: from datetime import datetime s = '24 October 2022' dt = datetime.strptime(s, '%d %B %Y').date() In [2]: print(dt) 2022-10-24 In [3]: type(dt) Out[3]: datetime.date Ref:- * https://stackoverflow.com/questions/9504356/convert-string-into-date-type-on-python - where I found the answer * https://docs.python.org/3/library/datetime.html#strftime-and-strptime-format-codes - shows the list of all the format codes such as %B, %Y. ==== series of date strings; using pandas ==== use df[col_name] = pd.to_datetime(df[col_name], format_str) For example $ ipython Python 3.10.6 | packaged by conda-forge | (main, Oct 24 2022, 16:02:16) [MSC v.1916 64 bit (AMD64)] Type 'copyright', 'credits' or 'license' for more information IPython 8.4.0 -- An enhanced Interactive Python. Type '?' for help. In [1]: import pandas as pd data = {'date': ["2022-10-24", "2022-10-08", "2022-09-06", "2022-08-08", "2022-06-06"], 'tag': ["3.11.0", "3.10.8", "3.10.7", "3.10.6", "3.10.5"]} df = pd.DataFrame(data) In [2]: print(df) date tag 0 2022-10-24 3.11.0 1 2022-10-08 3.10.8 2 2022-09-06 3.10.7 3 2022-08-08 3.10.6 4 2022-06-06 3.10.5 In [3]: print(df.dtypes) date object tag object dtype: object In [4]: df['date'] = pd.to_datetime(df['date'], format='%Y-%m-%d') In [5]: print(df) date tag 0 2022-10-24 3.11.0 1 2022-10-08 3.10.8 2 2022-09-06 3.10.7 3 2022-08-08 3.10.6 4 2022-06-06 3.10.5 In [6]: print(df.dtypes) date datetime64[ns] tag object dtype: object See also: https://pandas.pydata.org/docs/reference/api/pandas.to_datetime.html