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--- python_dictionaries [2023/02/26 03:18] – [tasks] raju
+++ python_dictionaries [2023/08/02 19:41] (current) – [find key corresponding to a value] raju
@@ Line 6: / Line 6: @@
   * [[Convert a string to a dictionary]]
+==== find key corresponding to a value ====
+The following will find the first key corresponding to a given value
+<code>
+>>> d ={1:'A', 2:'B', 3:'A', 4:'B'}
+>>> key_list = list(d.keys())
+>>> val_list = list(d.values())
+>>> lookup_val = 'A'
+>>> position = val_list.index(lookup_val)
+>>> key_val = key_list[position]
+>>> print(key_val)
+</code>
+<code>
+>>> lookup_val = 'B'
+>>> position = val_list.index(lookup_val)
+>>> key_val = key_list[position]
+>>> print(key_val)
+</code>
+Sample use case:
+  * In https://github.com/KamarajuKusumanchi/notebooks/blob/master/finvizfinance/target_price.ipynb , I used the above technique to find the index corresponding to 'Target Price'.
 ==== initialize a dictionary ====
@@ Line 119: / Line 142: @@
 Ref:- http://stackoverflow.com/questions/38987/how-to-merge-two-python-dictionaries-in-a-single-expression
+==== Convert a dictionary to a string ====
+<code>
+$ ipython
+Python 3.10.6 | packaged by conda-forge | (main, Oct 24 2022, 16:02:16) [MSC v.1916 64 bit (AMD64)]
+Type 'copyright', 'credits' or 'license' for more information
+IPython 8.4.0 -- An enhanced Interactive Python. Type '?' for help.
+In [1]:
+d = {'a':1, 'b':2}
+In [2]:
+import json
+s = json.dumps(d)
+In [3]:
+d
+Out[3]:
+{'a': 1, 'b': 2}
+In [4]:
+s
+Out[4]:
+'{"a": 1, "b": 2}'
+In [5]:
+type(d)
+Out[5]:
+dict
+In [6]:
+type(s)
+Out[6]:
+str
+</code>