Create a function

import pandas as pd

def print_without_index(df: pd.DataFrame):
    blank_index = [""] * len(df)
    original_index = df.index
    df.index = blank_index
    print(df)
    df.index = original_index

Use it as follows:

In [2]:
row1 = (123, "2014-07-08 00:09:00", 1411)
row2 = (123, "2014-07-08 00:49:00", 1041)
row3 = (123, "2014-07-08 00:09:00", 1411)
data = [row1, row2, row3]
df = pd.DataFrame(data, columns=("User ID", "Enter Time", "Activity Number"))
df
Out[2]:
   User ID           Enter Time  Activity Number
0      123  2014-07-08 00:09:00             1411
1      123  2014-07-08 00:49:00             1041
2      123  2014-07-08 00:09:00             1411

In [3]:
print_without_index(df)
  User ID           Enter Time  Activity Number
      123  2014-07-08 00:09:00             1411
      123  2014-07-08 00:49:00             1041
      123  2014-07-08 00:09:00             1411

Verify that the original index remains unchanged

In [5]:
df
Out[5]:
   User ID           Enter Time  Activity Number
0      123  2014-07-08 00:09:00             1411
1      123  2014-07-08 00:49:00             1041
2      123  2014-07-08 00:09:00             1411

Tested with python 3.10.9, ipython 8.8.0, pandas 1.5.2

Ref:

• Original idea is from - https://stackoverflow.com/questions/24644656/how-to-print-pandas-dataframe-without-index
• To see it in action
  • https://github.com/KamarajuKusumanchi/rutils/blob/master/python3/lib/DataFrameUtils.py → print_without_index()
  • https://github.com/KamarajuKusumanchi/rutils/blob/master/python3/tests/lib/test_DataFrameUtils.py → test_print_without_index()